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SMK Teknologi dan Rekayasa

Solusi Paket 59 UN 2011 Matematika SMK Teknologi (32)


Simpangan\ baku\ dari\ data:\ \ 10,\ 9,\ 3,\ 1,\ 7\ \ adalah\ ....\\A.\ \ \sqrt{2}\ \ \ \ \ \ \ \ \ \ B.\ \ \sqrt{3}\ \ \ \ \ \ \ \ \ \ C.\ \ 2\sqrt{2}\ \ \ \ \ \ \ \ \ \ D.\ \ 2\sqrt{3}\ \ \ \ \ \ \ \ \ \ E.\ \ 6\sqrt{2}
Jawaban: D
Rumus Simpangan Baku data tunggal:
Simpangan\ Baku=\sqrt{\frac{\sum(x-\bar{x})^{2}}{n}}
Data:\ \ \ \ 10,\ 9,\ 3,\ 1,\ 7\ \ \ \ \to \ \ \ \ n=5\\\\Rata-rata:\ \ \ \ \ \ \ \ \ \bar{x}=\frac{10+9+3+1+7}{5}=\frac{30}{5}=6

x

10

9

3

1

7

Jumlah

x-\bar{x}

10 – 6 = 4

9 – 6 = 3

3 – 6 = -3

1 – 6 = -5

7 – 6 = 1

(x-\bar{x})^2

16

9

9

25

1

60

Simpangan\ baku=\sqrt{\frac{60}{5}}=\sqrt{12}=\sqrt{4.3}=\sqrt{4}\times \sqrt{3}=2\sqrt{3}

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