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SMK Teknologi dan Rekayasa

Solusi Paket 59 UN 2011 Matematika SMK Teknologi (20)


Sebuah\ prisma\ tegak\ ABC.DEF\ dengan\ alas\ segitiga\ siku-siku\ di\ titik\ B.\\Jika\ panjang\ AB=5\ cm,\ BC=12\ cm,\ AC=13\ cm,\ dan\ AD=15\ cm,\\volume\ prisma\ tersebut\ adalah\ ....\\A.\ \ 135\ cm^{3}\ \ \ \ \ \ \ \ \ \ B.\ \ 225\ cm^{3}\ \ \ \ \ \ \ \ \ \ C.\ \ 450\ cm^{3}\ \ \ \ \ \ \ \ \ \ D.\ \ 650\ cm^{3}\ \ \ \ \ \ \ \ \ \ E.\ \ 725\ cm^{3}
Jawaban: C

\begin{array}{rcl}Volume\ prisma&=&luas\ alas\ \times\ tinggi\\\\&=&\frac{1}{2}\times AB\times BC\times AD\\\\&=&\frac{1}{2}\times 5\times 12\times 15\\\\&=&450\ cm^{3}\end{array}

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Guru Matematika SMK

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2 thoughts on “Solusi Paket 59 UN 2011 Matematika SMK Teknologi (20)

  1. Kalo bisa Pak di upload semua soalx, biar qta ikut belajar,,,

    Posted by HERIVENDI | 28 April 2011, 8:38 PM

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