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SMK Teknologi dan Rekayasa

Solusi Paket 59 UN 2011 Matematika SMK Teknologi (1)


Jika\ \ ^{3}log\ 7=a,\ maka\ \ ^{27}log\ 49=\ ....\\A.\ \ \frac{2a}{3}\ \ \ \ \ \ \ \ \ B.\ \ \frac{3}{2a}\ \ \ \ \ \ \ \ \ C.\ \ \frac{3}{2}a\ \ \ \ \ \ \ \ \ D.\ \ 2a-3\ \ \ \ \ \ \ \ \ E.\ \ 3-2a
Jawaban: A

\begin{array}{rcl}^{27}log\ 49&=&^{3^{3}}log\ 7^{2}\\\\&=&\frac{2}{3}\ \times \ ^{3}log\ 7\\\\&=&\frac{2}{3}\ \times \ a\\\\&=&\frac{2a}{3}\end{array}

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