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SMUP 2010

Solusi SMUP 2010 Kode 041 – Nomor 4


Jika\ pernyataan\ ''Jika\ x^2+x=6,\ maka\ x^2+3x<9''\\bernilai\ salah,\ maka\ nilai\ x\ sama\ dengan\ .... \\A.\quad -3\\B.\quad -2\\C.\quad -1\\D.\quad 1\\E.\quad 2
Jawaban: E

x^2+x=6\quad ...........\quad (1)\quad harus\ Benar
x^2+3x<9\quad ...........\quad (2)\quad harus\ Salah
Pernyataan (1) bernilai benar, jika:

\begin{array} {rcl} x^2+x&=&6\\x^2+x-6&=&0\\(x-2)(x+3)&=&0\end{array}
x=2\,\,\, atau\,\,\, x=-3
Substitusi x=2 ke (1) menghasilkan:

\begin{array} {rcl} 2^2+3.2&<&9\\4+6&<&9\end{array}
pernyataan yang Salah.

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