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USM ITT 2010

Solusi USM IT Telkom 2010 Kode 11 – Nomor 19


Nilai\ \lim\limits_{n \rightarrow 1} \frac{x^2+1}{x+1}\ adalah\ ....
(A)\quad 0\\(B)\quad 1\\(C)\quad \infty\\(D)\quad 2\\(E)\quad Tidak\ ada
Jawaban: B

\begin{array} {rcl} \lim\limits_{n \rightarrow 1} \frac{x^2+1}{x+1}&=&\frac{1^2+1}{1+1}\\\\&=&\frac{2}{2}\\\\&=&1\end{array}

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