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USM ITT 2010

Solusi USM IT Telkom 2010 Kode 11 – Nomor 17


Diketahui\ f(x)=2x-1\ dan\ f\circ g(x)=5x^2+7,\ maka\ g(2)=....\\(A)\quad 1\\(B)\quad 5\\(C)\quad 14\\(D)\quad 10\\(E)\quad 28
Jawaban: C

\begin{array} {rcl} f\circ g(x)&=&5x^2+7\\\\f(g(x))&=&5x^2+7\\\\2g(x)-1&=&5x^2+7\\\\2g(x)&=&5x^2+8\\\\g(x)&=&\frac{5}{2}x^2+4\end{array}
sehingga diperoleh:

\begin{array} {rcl} g(2)&=&\frac{5}{2}(2)^2+4\\\\&=&10+4\\\\&=&14\end{array}

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