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USM ITT 2010

Solusi USM IT Telkom 2010 Kode 11 – Nomor 16


Jika\ diketahui\ f(x)=sin(x),\ g(x)=x^2-x-6,\ dan\\h(x)=(f\circ g)(x)=f(g(x)),\ maka\ nilai\ h(3)h(1000)\ adalah\ ....\\(A)\quad 3\\(B)\quad 3000\\(C)\quad 333,33\\(D)\quad 1000\\(E)\quad 0
Jawaban: E

\begin{array} {rcl} h(x)&=&(f\circ g)(x)\\\\&=&f(g(x))\\\\&=&f(x^2-x-6)\\\\&=&sin(x^2-x-6)\end{array}
sehingga diperoleh:

\begin{array} {rcl} h(3)&=&sin(3^2-3-6)\\\\&=&sin0\\\\&=&0\end{array}
Jadi

h(3)h(1000)=0\times h(1000)=0

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