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SMK Teknologi dan Rekayasa

Soal 115 Turunan Fungsi Aljabar


Turunan\ kedua\ dari\ f(x)=4x^{3}-3x^{2}+8x-5\ adalah\ f{}''(x)=\ ....\\a.\ \ x^{4}-x^{3}+4x^{2}-5x\\b.\ \ 12x^{2}-6x+8\\c.\ \ 12x^{2}+6x+8\\d.\ \ 24x+6\\e.\ \ 24x-6
Jawaban: e

f(x)=4x^{3}-3x^{2}+8x-5
f{}'(x)=4.3x^{3-1}-3.2x^{2-1}2+8-0\\f{}'(x)=12x^{2}-6x+8
f{}''(x)=12.2x^{2-1}-6+0\\f{}''(x)=24x-6

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