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SMK Teknologi dan Rekayasa

Soal 108 Ukuran Pemusatan


Nilai\ matematika\ siswa\ kelas\ XII\ pada\ sebuah\ SMK\ tampak\ pada\ tabel\\di\ bawah\ ini.

Kuartil\ atas\ dari\ data\ tersebut\ adalah\ ....\\a.\ \ 80,6\ \ \ \ \ \ \ \ \ \ b.\ \ 81,6\ \ \ \ \ \ \ \ \ \ c.\ \ 82,6\ \ \ \ \ \ \ \ \ \ d.\ \ 83,6\ \ \ \ \ \ \ \ \ \ e.\ \ 84,6
Jawaban: b

Rumus\ Kuartil\ Atas\ data\ berkelompok:
\mathbf{Q_{3}=Tb+\left (\frac{\frac{3}{4}n-f_{k_{3}}}{f_{3}} \right )i}

\begin{array}{rcl}\frac{3}{4}\ n=\frac{3}{4}\times 44=33\ \ \ \ \ \to \ \ \ \ \ Kelas\ Q_{3}&=&81\ -\ 90\\Tb&=&81-0,5=80,5\\f_{k_{3}}&=&32\\f_{3}&=&9\\i&=&61-51=10\end{array}
\begin{array}{rcl}Q_{3}&=&80,5+\left (\frac{33-32}{9} \right )10\\\\&=&80,5+\left (\frac{1}{9} \right )10\\\\&=&80,5+1,1\\\\&=&81,6\end{array}

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2 thoughts on “Soal 108 Ukuran Pemusatan

  1. salam kenal

    Posted by mudahnyafisika | 20 Maret 2010, 9:50 AM

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