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SMK Teknologi dan Rekayasa

Soal 75 Negasi Pernyataan Majemuk


Ingkaran\ dari\ (p\to q)\wedge r\ adalah\ ....\\a.\ \ (p\wedge \sim q)\vee \sim r\ \ \ \ \ \ \ \ \ b.\ \ (p\wedge \sim q)\wedge \sim r\ \ \ \ \ \ \ \ \ c.\ \ p\wedge q\wedge \sim r\\d.\ \ \sim p\wedge \sim q\wedge r\ \ \ \ \ \ \ \ \ \ e.\ \ (\sim p\vee q)\wedge r
Jawaban: a

\begin{array}{rcl}\sim [(p\to q)\wedge r]&\equiv &\sim (p\to q)\vee \sim r\\&\equiv &(p\wedge \sim q)\vee \sim r\end{array}

Keterangan:\\Hukum\ De\ M\ddot{o}rgan:\ \ \sim (P\wedge Q)\equiv \sim P\vee \sim Q\\Pandanglah\ p\to q\equiv P\ dan\ r\equiv Q\\Selanjutnya,\ harus\ diingat\ bahwa:\\\sim (p\to q)\equiv p\wedge \sim q

About Kalakay

Guru Matematika SMK

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One thought on “Soal 75 Negasi Pernyataan Majemuk

  1. bagi soal matematika dong tentang bangun ruang 20 soal baru dapat 19 nie

    Posted by anggie | 8 April 2012, 11:15 AM

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