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SMK Teknologi dan Rekayasa

Soal 67 Volume Bangun Ruang


Gambar\ di\ bawah\ adalah\ potongan\ sebuah\ pipa\ logam.

Jari-jari\ bagian\ dalam\ pipa\ 2,1\ cm,\ jari-jari\ bagian\ luar\ pipa\ 2,5\ cm,\\dan\ panjang\ pipa\ 12\ cm.\ Volume\ logam\ yang\ digunakan\ untuk\ membuat\\pipa\ adalah\ ....\\a.\ \ 72,3\ cm^{3}\ \ \ \ \ \ \ \ \ \ b.\ \ 71,3\ cm^{3}\ \ \ \ \ \ \ \ \ \ c.\ \ 70,3\ cm^{3}\ \ \ \ \ \ \ \ \ \ d.\ \ 69,3\ cm^{3}\ \ \ \ \ \ \ \ \ \ e.\ \ 68,3\ cm^{3}
Jawaban: d

\begin{array}{rcl}Volume\ logam&=&volume\ tabung\ luar\ -\ volume\ tabung\ dalam\\\\&=&\pi R^{2}t-\pi r^{2}t\\\\&=&\pi t(R^{2}-r^{2})\\\\&=&3,14\times 12\times (2,5^{2}-2,1^{2})\\\\&=&37,68\times (6,25-4,41)\\\\&=&37,68\times 1,84\\\\&=&69,3312\\\\&=&69,3\ cm^{3}\end{array}
(pembulatan\ sampai\ dengan\ dua\ tempat\ desimal)

About Kalakay

Guru Matematika SMK

Diskusi

2 thoughts on “Soal 67 Volume Bangun Ruang

  1. Teruskan berbaginya sobat
    Salam kenal

    Posted by cobaberbagi | 26 Maret 2010, 4:18 PM

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