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SMK Teknologi dan Rekayasa

Soal 57 Luas Bangun Datar


Perhatikan\ gambar\ di\ bawah\ ini!

Jika\ \pi =\frac{22}{7},\ maka\ luas\ yang\ diarsir\ adalah\ ....
a.\ \ 184\ cm^{2}\ \ \ \ \ \ \ \ \ \ b.\ \ 217\ cm^{2}\ \ \ \ \ \ \ \ \ \ c.\ \ 294\ cm^{2}\ \ \ \ \ \ \ \ \ \ d.\ \ 357\ cm^{2}\ \ \ \ \ \ \ \ \ \ e.\ \ 434\ cm^{2}
Jawaban: b

\begin{array}{rcl}Luas\ yang\ diarsir&=&luas\ setengah\ lingkaran\ +\ luas\ segitiga\\\\&=&\frac{1}{2}\pi r^{2}+\frac{1}{2}at\\\\&=&\frac{1}{2}\times \frac{22}{7}\times 7\times 7+\frac{1}{2}\times 14\times 20\\\\&=&77+140\\\\&=&217\ cm^{2}\end{array}

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