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SMK Teknologi dan Rekayasa

Soal 15 Logaritma


Jika\ \ ^{2}log 3\ =\ a,\ maka\ \ ^{64}log 27\ =\ ....\\a.\ \ \frac{a}{2}\ \ \ \ \ \ \ \ \ b.\ \ \frac{1}{2a}\ \ \ \ \ \ \ \ \ c.\ \ \frac{1}{3a}\ \ \ \ \ \ \ \ \ d.\ \ 2a\ \ \ \ \ \ \ \ \ e.\ \ 3a

Jawaban: a

\begin{array}{rcl}^{64}log 27&=&^{2^{6}}log3^{3}\\\\&=&\frac{3}{6}\ \times \ ^{2}log3\\\\&=&\frac{1}{2}\ \times \ a\\\\&=&\frac{a}{2}\end{array}

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2 thoughts on “Soal 15 Logaritma

  1. jawaban salah.. yang benar A.

    Posted by fahrudin | 8 April 2014, 3:09 PM

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