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SMK Teknologi dan Rekayasa

Soal 10 Pecahan Bentuk Akar


\frac{\sqrt{3}-2}{\sqrt{3}+2}=....
a.\ \ -7-4\sqrt{3}\ \ \ \ \ \ b.\ -7+4\sqrt{3}\ \ \ \ \ \ c.\ -1+\frac{4}{7}\sqrt{3}\ \ \ \ \ \ d.\ \ 1-\frac{4}{7}\sqrt{3}\ \ \ \ \ \ e.\ \ 1+4\sqrt{3}
Jawaban: b

\begin{array}{rcl}\frac{\sqrt{3}-2}{\sqrt{3}+2}&=&\frac{\sqrt{3}-2}{\sqrt{3}+2}\ \times\ \frac{\sqrt{3}-2}{\sqrt{3}-2}\\\\&=&\frac{(\sqrt{3}-2)^{2}}{(\sqrt{3})^{2}-2^{2}}\\\\&=&\frac{(\sqrt{3})^{2}-2.2.\sqrt{3}+2^{2}}{3-4}\\\\&=&\frac{3-4\sqrt{3}+4}{-1}\\\\&=&\frac{7-4\sqrt{3}}{-1}\\\\&=&-7+4\sqrt{3}\end{array}

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2 thoughts on “Soal 10 Pecahan Bentuk Akar

  1. soal ini agak rumit ya caranya

    Posted by elda oktaviani | 16 Oktober 2011, 10:10 PM
  2. Harus nya yang disamakan yang penyebut, bukan pembilang

    Posted by Brandon | 24 Januari 2016, 10:03 PM

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