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SMK Teknologi dan Rekayasa

Soal 6 Perpangkatan


Jika\ x=9\ dan\ y=64\ ,\ maka\ nilai\ 6x^{-0,5}.y^{\frac{1}{3}}=....\\a.\ \ \frac{1}{2}\ \ \ \ \ \ b.\ \ 8\ \ \ \ \ \ c.\ \ -3\ \ \ \ \ \ d.\ \ 1\ \ \ \ \ \ e.\ \ 72
Jawaban: b
\begin{array}{rcl}6\ x^{-0,5}\ .\ y^{\frac{1}{3}}&=&6\times 9^{-0,5}\times 64^{\frac{1}{3}}\\\\&=&6\times (3^{2})^{-0,5}\times (4^3)^{\frac{1}{3}}\\\\&=&6\times 3^{2\times (-0,5)}\times 4^{3\times \frac{1}{3}}\\\\&=&6\times 3^{-1}\times 4^{1}\\\\&=&6\times \frac{1}{3}\times 4\\\\&=&8\end{array}

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