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	<title>Soal-Jawab Matematika</title>
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		<title>Soal-Jawab Matematika</title>
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		<title>Tinjauan &#8220;Soal-Jawab Matematika&#8221; Tahun 2011</title>
		<link>http://qedems.wordpress.com/2012/01/01/2011-in-review/</link>
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		<pubDate>Sun, 01 Jan 2012 15:23:22 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[Zonk]]></category>

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		<description><![CDATA[The WordPress.com stats helper monkeys prepared a 2011 annual report for this blog. Here&#8217;s an excerpt: The Louvre Museum has 8.5 million visitors per year. This blog was viewed about 170.000 times in 2011. If it were an exhibit at the Louvre Museum, it would take about 7 days for that many people to see &#8230; <a href="http://qedems.wordpress.com/2012/01/01/2011-in-review/">Continue reading <span class="meta-nav">&#187;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5207&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>The WordPress.com stats helper monkeys prepared a 2011 annual report for this blog.</p>
<p><a href="/2011/annual-report/"><img src="http://www.wordpress.com/wp-content/mu-plugins/annual-reports/img/emailteaser.jpg" alt="" width="100%" /></a></p>
<p>Here&#8217;s an excerpt:</p>
<blockquote><p>The Louvre Museum has 8.5 million visitors per year. This blog was viewed about <strong>170.000</strong> times in 2011. If it were an exhibit at the Louvre Museum, it would take about 7 days for that many people to see it.</p></blockquote>
<p><span style="color:#800000;"><a href="/2011/annual-report/"><span style="color:#800000;">Selengkapnya dapat Anda lihat di sini.</span></a></span></p>
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			<media:title type="html">Kalakay</media:title>
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		<title>Kisi-kisi Ujian Nasional 2012 Matematika SMK Teknologi</title>
		<link>http://qedems.wordpress.com/2011/12/16/kisi-kisi-ujian-nasional-2012-matematika-smk-teknologi/</link>
		<comments>http://qedems.wordpress.com/2011/12/16/kisi-kisi-ujian-nasional-2012-matematika-smk-teknologi/#comments</comments>
		<pubDate>Fri, 16 Dec 2011 13:29:28 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Kisi-kisi]]></category>
		<category><![CDATA[Kisi-kisi UN 2012]]></category>
		<category><![CDATA[Kisi-kisi UN 2012 SMK Teknologi]]></category>

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		<description><![CDATA[Sebelum penulis melanjutkan tulisan sebelumnya, penulis akan tunjukkan dulu Kisi-kisi UN 2012 Matematika SMK Teknologi karena (tentu saja) ini menjadi acuan dalam persiapan menuju UN 2012. Ada beberapa perubahan pada indikator UN 2012 ini bila dibandingkan dengan indikator pada UN 2011 dan yang paling menonjol adalah ditambahkannya materi baru yang diujikan, yaitu Irisan Kerucut (lingkaran &#8230; <a href="http://qedems.wordpress.com/2011/12/16/kisi-kisi-ujian-nasional-2012-matematika-smk-teknologi/">Continue reading <span class="meta-nav">&#187;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5204&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Sebelum penulis melanjutkan tulisan sebelumnya, penulis akan tunjukkan dulu Kisi-kisi UN 2012 Matematika SMK Teknologi karena (tentu saja) ini menjadi acuan dalam persiapan menuju UN 2012.</p>
<p>Ada beberapa perubahan pada indikator UN 2012 ini bila dibandingkan dengan indikator pada UN 2011 dan yang paling menonjol adalah ditambahkannya materi baru yang diujikan, yaitu Irisan Kerucut (lingkaran atau parabola).</p>
<p>Berikut ini penulis sajikan selengkapnya Kompetensi dan Indikator yang tercantum pada Kisi-kisi UN 2012 Matematika SMK Teknologi.</p>
<table border="0" cellpadding="0">
<tbody>
<tr>
<td width="217">
<p align="center"><strong>KOMPETENSI</strong><strong></strong></p>
</td>
<td width="384">
<p align="center"><strong>INDIKATOR</strong></p>
</td>
</tr>
<tr>
<td rowspan="2" valign="top" width="217">Melakukan operasi bilangan real dan menerapkannya dalam bidang kejuruan</td>
<td width="384">Menyelesaikan masalah dengan menggunakan operasi bilangan real</td>
</tr>
<tr>
<td width="384">Menentukan hasil operasi bilangan berpangkat dan bentuk akar, dan/atau logaritma</td>
</tr>
<tr>
<td valign="top" width="217">Memecahkan masalah yang berkaitan dengan sistem persamaan dan pertidaksamaan linear dua variable serta dapat menerapkannya dalam bidang kejuruan</td>
<td valign="top" width="384">Menyelesaikan masalah sistem persamaan atau pertidaksamaan linear dua variabel</td>
</tr>
<tr>
<td rowspan="5" valign="top" width="217">Menyelesaikan masalah yang berkaitan dengan fungsi linear, fungsi kuadrat, dan program linear</td>
<td width="384">Menentukan fungsi linear dan/atau grafiknya</td>
</tr>
<tr>
<td width="384">Menentukan fungsi kuadrat dan/atau grafiknya</td>
</tr>
<tr>
<td width="384">Menentukan model matematika dari masalah program linear</td>
</tr>
<tr>
<td width="384">Menentukan daerah himpunan penyelesaian dari masalah program linear</td>
</tr>
<tr>
<td width="384">Menentukan nilai optimum dari sistem pertidaksamaan linear</td>
</tr>
<tr>
<td rowspan="2" valign="top" width="217">Menerapkan konsep matriks dan vektor untuk memecahkan masalah</td>
<td width="384">Menentukan hasil operasi matriks atau invers suatu matriks</td>
</tr>
<tr>
<td width="384">Menentukan hasil operasi vektor dan besar sudut antar vektor pada bidang atau ruang</td>
</tr>
<tr>
<td rowspan="3" valign="top" width="217">Menerapkan prinsip-prinsip logika matematika dalam pemecahan masalah yang berkaitan dengan pernyataan majemuk dan pernyataan berkuantor</td>
<td width="384">Menentukan ingkaran dari suatu pernyataan</td>
</tr>
<tr>
<td width="384">Menentukan invers, konvers, atau kontraposisi</td>
</tr>
<tr>
<td width="384">Menarik kesimpulan dari beberapa premis</td>
</tr>
<tr>
<td rowspan="4" valign="top" width="217">Menentukan unsur-unsur bangun datar, keliling dan luas bangun datar, luas permukaan dan volum bangun ruang, unsur-unsur irisan kerucut serta dapat menerapkannya dalam bidang kejuruan</td>
<td width="384">Mengidentifikasi bangun datar, bangun ruang, dan unsur-unsurnya</td>
</tr>
<tr>
<td width="384">Menghitung keliling dan luas bangun datar atau menyelesaikan masalah yang terkait</td>
</tr>
<tr>
<td width="384">Menghitung luas bangun permukaan bangun ruang atau menyelesaikan masalah yang terkait</td>
</tr>
<tr>
<td width="384">Menghitung volum bangun ruang atau menyelesaikan masalah yang terkait</td>
</tr>
<tr>
<td rowspan="2" valign="top" width="217">Menerapkan konsep perbandingan trigonometri dalam pemecahan masalah</td>
<td width="384">Menentukan unsur-unsur segitiga dengan menggunakan perbandingan trigonometri</td>
</tr>
<tr>
<td width="384">Mengkonversi koordinat kutub ke koordinat kartesius atau sebaliknya</td>
</tr>
<tr>
<td rowspan="3" valign="top" width="217">Memecahkan masalah yang berkaitan dengan barisan dan deret</td>
<td width="384">Mengidentifikasi pola, barisan, atau deret bilangan</td>
</tr>
<tr>
<td width="384">Menyelesaikan masalah yang berkaitan dengan barisan atau deret aritmetika</td>
</tr>
<tr>
<td width="384">Menyelesaikan masalah yang berkaitan dengan barisan dan deret geometri</td>
</tr>
<tr>
<td rowspan="2" valign="top" width="217">Menerapkan konsep peluang dalam pemecahan masalah</td>
<td width="384">Menentukan permutasi atau kombinasi</td>
</tr>
<tr>
<td width="384">Menghitung peluang suatu kejadian atau frekuensi harapannya</td>
</tr>
<tr>
<td rowspan="3" valign="top" width="217">Menerapkan konsep dan pengukuran statistik dalam pemecahan masalah</td>
<td width="384">Menginterpretasi data yang disajikan dalam bentuk tabel atau diagram</td>
</tr>
<tr>
<td width="384">Menghitung ukuran pemusatan data</td>
</tr>
<tr>
<td width="384">Menghitung ukuran penyebaran data</td>
</tr>
<tr>
<td rowspan="2" valign="top" width="217">Menggunakan konsep limit fungsi dan turunan fungsi dalam pemecahan masalah</td>
<td width="384">Menentukan limit fungsi aljabar atau fungsi trigonometri</td>
</tr>
<tr>
<td width="384">Menentukan turunan fungsi aljabar atau fungsi trigonometri</td>
</tr>
<tr>
<td rowspan="3" valign="top" width="217">Menggunakan konsep integral dalam pemecahanan masalah</td>
<td width="384">Menentukan integral tak tentu atau integral tentu dari fungsi aljabar atau trigonometri</td>
</tr>
<tr>
<td width="384">Menentukan luas daerah di antara dua kurva</td>
</tr>
<tr>
<td width="384">Menentukan volum benda putar</td>
</tr>
<tr>
<td width="217">Menerapkan konsep irisan kerucut dalam memecahkan masalah</td>
<td width="384">Menyelesaikan model matematika dari masalah yang berkaitan dengan lingkaran atau parabola</td>
</tr>
</tbody>
</table>
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			<media:title type="html">Kalakay</media:title>
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		<item>
		<title>Pelatihan Menuju UN 2012</title>
		<link>http://qedems.wordpress.com/2011/12/04/pelatihan-menuju-un-2012/</link>
		<comments>http://qedems.wordpress.com/2011/12/04/pelatihan-menuju-un-2012/#comments</comments>
		<pubDate>Sat, 03 Dec 2011 17:08:03 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Pelatihan UN 2012]]></category>
		<category><![CDATA[Siap UN 2012]]></category>
		<category><![CDATA[UN 2012]]></category>

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		<description><![CDATA[Berdasarkan informasi terakhir Ujian Nasional Tahun Pelajaran 2011/2012 untuk tingkat SMA/MA/SMK akan dilaksanakan pada 16 s.d. 19 April 2012. Sehubungan dengan hal itu penulis mengajak para siswa Kelas 12 SMK Teknologi untuk menyiapkan diri sejak saat ini! Untuk membantu persiapan para calon peserta UN 2012 tersebut kali ini penulis telah menyiapkan tulisan yang dapat diunduh. &#8230; <a href="http://qedems.wordpress.com/2011/12/04/pelatihan-menuju-un-2012/">Continue reading <span class="meta-nav">&#187;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5193&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Berdasarkan informasi terakhir Ujian Nasional Tahun Pelajaran 2011/2012 untuk tingkat SMA/MA/SMK akan dilaksanakan pada 16 s.d. 19 April 2012. Sehubungan dengan hal itu penulis mengajak para siswa Kelas 12 SMK Teknologi untuk menyiapkan diri sejak saat ini!</p>
<p>Untuk membantu persiapan para calon peserta UN 2012 tersebut kali ini penulis telah menyiapkan tulisan yang dapat diunduh. Pada tiap halaman tulisan tersebut terbagi dalam dua kolom, yaitu ringkasan materi (di kiri) dan soal-soal (di kanan). Tiap halaman mewakili satu kemampuan yang diuji sebagaimana tercantum pada Kisi-kisi Ujian Nasional. Penulis beranggapan bahwa materi pada UN 2012 masih sama dengan materi UN 2011, karena itu tulisan tersebut mengacu pada <a href="http://idws.us/bbcibdf">Kisi-kisi UN 2011</a>. Adapun soal-soalnya penulis seleksi dari berbagai sumber (yang bersesuaian dengan kisi-kisi tersebut).</p>
<p>Nah, berikut ini materi dan soal Matematika untuk Anda berlatih dalam persiapan menuju UN 2012.</p>
<ol>
<li><span style="color:#800000;"><a href="http://idws.us/bbciabf"><span style="color:#800000;">Menyelesaikan masalah yang berkaitan dengan untung rugi</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciabg"><span style="color:#800000;">Menyelesaikan masalah yang berkaitan dengan perbandingan</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciabh"><span style="color:#800000;">Menentukan hasil operasi bilangan berpangkat</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciaga"><span style="color:#800000;">Menyederhanakan bentuk akar</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciagb"><span style="color:#800000;">Menentukan nilai dari operasi bentuk logaritma</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciagc"><span style="color:#800000;">Menentukan gradien atau persamaan garis</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciajc"><span style="color:#800000;">Menentukan titik potong, titik puncak, atau persamaan grafik fungsi kuadrat</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciajd"><span style="color:#800000;">Menentukan himpunan penyelesaian pertidaksamaan linear satu variabel</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbciaje"><span style="color:#800000;">Menyelesaikan masalah sistem persamaan linear dua variabel</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibba"><span style="color:#800000;">Menentukan model matematika atau daerah himpunan penyelesaian sistem pertidaksamaan linear</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibbb"><span style="color:#800000;">Menentukan nilai optimum fungsi objektif</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibbc"><span style="color:#800000;">Menentukan hasil operasi pada matriks</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibcg"><span style="color:#800000;">Menentukan unsur-unsur yang belum diketahui pada kesamaan dua matriks</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibch"><span style="color:#800000;">Menentukan hasil operasi pada vektor</span></a></span></li>
<li><span style="color:#800000;"><a href="http://idws.us/bbcibci"><span style="color:#800000;">Menentukan besar sudut antara dua vektor</span></a></span></li>
</ol>
<p><span style="color:#993366;">(Masih terdapat beberapa materi lagi yang belum termuat di sini, insyaallah akan penulis sambung terus pada kesempatan lain)</span></p>
<p>Selamat belajar dan tetap semangat!</p>
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			<media:title type="html">Kalakay</media:title>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (40)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-40/</link>
		<comments>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-40/#comments</comments>
		<pubDate>Tue, 03 May 2011 11:32:28 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5182</guid>
		<description><![CDATA[Jawaban: B Alternatif 1, dengan menggunakan faktorisasi Alternatif 2, dengan menggunakan turunan/diferensial (Dalil L&#8217;Hospital)<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5182&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B2x%5E2%2B5x-3%7D%7Bx%5E2%2Bx-6%7D%3D+....%5C%5C%5C%5CA.%5C+%5C+0%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+B.%5C+%5C+%5Cfrac%7B7%7D%7B5%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+C.%5C+%5C+%5Cfrac%7B17%7D%7B7%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+D.%5C+%5C+3%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+E.%5C+%5C+5+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}= ....&#92;&#92;&#92;&#92;A.&#92; &#92; 0&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; &#92;frac{7}{5}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; &#92;frac{17}{7}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; 3&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; 5 ' title='&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}= ....&#92;&#92;&#92;&#92;A.&#92; &#92; 0&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; &#92;frac{7}{5}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; &#92;frac{17}{7}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; 3&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; 5 ' class='latex' /><br />
Jawaban: B<br />
<span style="color:#800000;"><strong>Alternatif 1</strong></span>, dengan menggunakan faktorisasi<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7D%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B2x%5E2%2B5x-3%7D%7Bx%5E2%2Bx-6%7D%26%3D%26%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B%282x-1%29%28x%2B3%29%7D%7B%28x-2%29%28x%2B3%29%7D%5C%5C%5C%5C%26%3D%26%5Clim%5Climits_%7Bx%5C+%5Crightarrow+%5C+-3%7D+%5Cfrac%7B2x-1%7D%7Bx-2%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B2%28-3%29-1%7D%7B-3-2%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-6-1%7D%7B-5%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-7%7D%7B-5%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B7%7D%7B5%7D%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='&#92;begin{array}{rcl}&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{(2x-1)(x+3)}{(x-2)(x+3)}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;lim&#92;limits_{x&#92; &#92;rightarrow &#92; -3} &#92;frac{2x-1}{x-2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{2(-3)-1}{-3-2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-6-1}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-7}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{7}{5}&#92;end{array} ' title='&#92;begin{array}{rcl}&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{(2x-1)(x+3)}{(x-2)(x+3)}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;lim&#92;limits_{x&#92; &#92;rightarrow &#92; -3} &#92;frac{2x-1}{x-2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{2(-3)-1}{-3-2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-6-1}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-7}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{7}{5}&#92;end{array} ' class='latex' /><br />
<span style="color:#800000;"><strong>Alternatif 2</strong></span>, dengan menggunakan turunan/diferensial (Dalil L&#8217;Hospital)<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7D%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B2x%5E2%2B5x-3%7D%7Bx%5E2%2Bx-6%7D%26%3D%26%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B2%282%29x%2B5-0%7D%7B2x%2B1-0%7D%5C%5C%5C%5C%26%3D%26%5Clim%5Climits_%7Bx%5Crightarrow+-3%7D+%5Cfrac%7B4x%2B5%7D%7B2x%2B1%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B4%28-3%29%2B5%7D%7B2%28-3%29%2B1%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-12%2B5%7D%7B-6%2B1%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-7%7D%7B-5%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B7%7D%7B5%7D%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='&#92;begin{array}{rcl}&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2(2)x+5-0}{2x+1-0}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{4x+5}{2x+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{4(-3)+5}{2(-3)+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-12+5}{-6+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-7}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{7}{5}&#92;end{array} ' title='&#92;begin{array}{rcl}&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2x^2+5x-3}{x^2+x-6}&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{2(2)x+5-0}{2x+1-0}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;lim&#92;limits_{x&#92;rightarrow -3} &#92;frac{4x+5}{2x+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{4(-3)+5}{2(-3)+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-12+5}{-6+1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-7}{-5}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{7}{5}&#92;end{array} ' class='latex' /></p>
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			<media:title type="html">Kalakay</media:title>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (39)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-39/</link>
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		<pubDate>Tue, 03 May 2011 10:54:14 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5171</guid>
		<description><![CDATA[Jawaban: E Trik jitu: Karena setiap pilihan jawaban memiliki penyebut yang sama maka cukup ditentukan pembilangnya saja, yaitu:<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5171&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=Jika%5C+f%28x%29%3D%5Cfrac%7B-x%2B3%7D%7B4x-1%7D%2C%5C+dengan%5C+x%5Cne+%5Cfrac%7B1%7D%7B4%7D%5C+maka%5C+turunan%5C+pertama%5C+dari%5C+f%28x%29%5C+adalah%5C%5Cf%7B%7D%27%28x%29%3D%5C+....%5C%5C%5C%5CA.%5C+%5C+%5Cfrac%7B11%7D%7B%284x-1%29%5E%7B2%7D%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+B.%5C+%5C+%5Cfrac%7B-4%7D%7B%284x-1%29%5E%7B2%7D%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+C.%5C+%5C+%5Cfrac%7B-8x%2B13%7D%7B%284x-1%29%5E%7B2%7D%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+D.%5C+%5C+%5Cfrac%7B-5%7D%7B%284x-1%29%5E%7B2%7D%7D%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+E.%5C+%5C+%5Cfrac%7B-11%7D%7B%284x-1%29%5E%7B2%7D%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Jika&#92; f(x)=&#92;frac{-x+3}{4x-1},&#92; dengan&#92; x&#92;ne &#92;frac{1}{4}&#92; maka&#92; turunan&#92; pertama&#92; dari&#92; f(x)&#92; adalah&#92;&#92;f{}&#039;(x)=&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; &#92;frac{11}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; &#92;frac{-4}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; &#92;frac{-8x+13}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; &#92;frac{-5}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; &#92;frac{-11}{(4x-1)^{2}} ' title='Jika&#92; f(x)=&#92;frac{-x+3}{4x-1},&#92; dengan&#92; x&#92;ne &#92;frac{1}{4}&#92; maka&#92; turunan&#92; pertama&#92; dari&#92; f(x)&#92; adalah&#92;&#92;f{}&#039;(x)=&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; &#92;frac{11}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; &#92;frac{-4}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; &#92;frac{-8x+13}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; &#92;frac{-5}{(4x-1)^{2}}&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; &#92;frac{-11}{(4x-1)^{2}} ' class='latex' /><br />
Jawaban: E<br />
<img src='http://s0.wp.com/latex.php?latex=u%28x%29%3D-x%2B3%5C+%5C+%5C+%5C+%5C+%5Cto+%5C+%5C+%5C+%5C+%5C+u%7B%7D%27%28x%29%3D-1%2B0%3D-1%5C%5Cv%28x%29%3D4x-1%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5Cto+%5C+%5C+%5C+%5C+%5C+v%7B%7D%27%28x%29%3D4-0%3D4+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='u(x)=-x+3&#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; u{}&#039;(x)=-1+0=-1&#92;&#92;v(x)=4x-1&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; v{}&#039;(x)=4-0=4 ' title='u(x)=-x+3&#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; u{}&#039;(x)=-1+0=-1&#92;&#92;v(x)=4x-1&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; v{}&#039;(x)=4-0=4 ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7Df%7B%7D%27%28x%29%26%3D%26%5Cfrac%7Bu%7B%7D%27.v-u.v%7B%7D%27%7D%7Bv%5E%7B2%7D%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-1.%284x-1%29-%28-x%2B3%29.4%7D%7B%284x-1%29%5E%7B2%7D%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-4x%2B1%2B4x-12%7D%7B%284x-1%29%5E%7B2%7D%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B-11%7D%7B%284x-1%29%5E%7B2%7D%7D%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='&#92;begin{array}{rcl}f{}&#039;(x)&amp;=&amp;&#92;frac{u{}&#039;.v-u.v{}&#039;}{v^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-1.(4x-1)-(-x+3).4}{(4x-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-4x+1+4x-12}{(4x-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-11}{(4x-1)^{2}}&#92;end{array} ' title='&#92;begin{array}{rcl}f{}&#039;(x)&amp;=&amp;&#92;frac{u{}&#039;.v-u.v{}&#039;}{v^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-1.(4x-1)-(-x+3).4}{(4x-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-4x+1+4x-12}{(4x-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{-11}{(4x-1)^{2}}&#92;end{array} ' class='latex' /><br />
<span style="color:#0000ff;"><strong>Trik jitu</strong></span>:<br />
<img src='http://s0.wp.com/latex.php?latex=f%28x%29%3D%5Cfrac%7Bax%2Bb%7D%7Bcx%2Bd%7D%5C+%5C+%5C+%5C+%5C+%5Cto+%5C+%5C+%5C+%5C+%5C+f%7B%7D%27%28x%29%3D%5Cfrac%7Ba.d-b.c%7D%7B%28cx%2Bd%29%5E%7B2%7D%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='f(x)=&#92;frac{ax+b}{cx+d}&#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; f{}&#039;(x)=&#92;frac{a.d-b.c}{(cx+d)^{2}} ' title='f(x)=&#92;frac{ax+b}{cx+d}&#92; &#92; &#92; &#92; &#92; &#92;to &#92; &#92; &#92; &#92; &#92; f{}&#039;(x)=&#92;frac{a.d-b.c}{(cx+d)^{2}} ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=f%28x%29%3D%5Cfrac%7B-x%2B3%7D%7B4x-1%7D%5Cqquad+%5Crightarrow+%5Cqquad+a%3D-1%2C%5C+b%3D3%2C%5C+c%3D4%2C%5C+d%3D-1+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='f(x)=&#92;frac{-x+3}{4x-1}&#92;qquad &#92;rightarrow &#92;qquad a=-1,&#92; b=3,&#92; c=4,&#92; d=-1 ' title='f(x)=&#92;frac{-x+3}{4x-1}&#92;qquad &#92;rightarrow &#92;qquad a=-1,&#92; b=3,&#92; c=4,&#92; d=-1 ' class='latex' /><br />
Karena setiap pilihan jawaban memiliki penyebut yang sama maka cukup ditentukan pembilangnya saja, yaitu:<br />
<img src='http://s0.wp.com/latex.php?latex=a.d-b.c%3D-1.%28-1%29-4.3%3D1-12%3D-11+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a.d-b.c=-1.(-1)-4.3=1-12=-11 ' title='a.d-b.c=-1.(-1)-4.3=1-12=-11 ' class='latex' /></p>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (38)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-38/</link>
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		<pubDate>Tue, 03 May 2011 09:48:26 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5164</guid>
		<description><![CDATA[Jawaban: D<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5164&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=Hasil%5C+dari%5C+%5Cint_%7B2%7D%5E%7B3%7D%2812x%5E%7B2%7D-5%29%5C+adalah%5C+....%5C%5C%5C%5CA.%5C+%5C+24%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+B.%5C+%5C+51%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+C.%5C+%5C+60%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+D.%5C+%5C+71%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+%5C+E.%5C+%5C+98+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Hasil&#92; dari&#92; &#92;int_{2}^{3}(12x^{2}-5)&#92; adalah&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; 24&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; 51&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; 60&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; 71&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; 98 ' title='Hasil&#92; dari&#92; &#92;int_{2}^{3}(12x^{2}-5)&#92; adalah&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; 24&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; B.&#92; &#92; 51&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; C.&#92; &#92; 60&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; D.&#92; &#92; 71&#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; &#92; E.&#92; &#92; 98 ' class='latex' /><br />
Jawaban: D<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7D%5Cint_%7B2%7D%5E%7B3%7D%2812x%5E%7B2%7D-5%29%5C+dx%26%3D%26%5CBig%5B12%5Ctimes+%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D-5x%5CBig%5D_%7B2%7D%5E%7B3%7D%5C%5C%5C%5C%26%3D%26%5CBig%5B4x%5E%7B3%7D-5x%5CBig%5D_%7B2%7D%5E%7B3%7D%5C%5C%5C%5C%26%3D%26%5Cbig%284%5Ctimes+3%5E%7B3%7D-5%5Ctimes+3%5Cbig%29-%5Cbig%284%5Ctimes+2%5E%7B3%7D-5%5Ctimes+2%5Cbig%29%5C%5C%5C%5C%26%3D%26%5Cbig%284%5Ctimes+27-15%5Cbig%29-%5Cbig%284%5Ctimes+8-10%5Cbig%29%5C%5C%5C%5C%26%3D%26%28108-15%29-%2832-10%29%5C%5C%5C%5C%26%3D%2693-22%5C%5C%5C%5C%26%3D%2671%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}&#92;int_{2}^{3}(12x^{2}-5)&#92; dx&amp;=&amp;&#92;Big[12&#92;times &#92;frac{x^{3}}{3}-5x&#92;Big]_{2}^{3}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;Big[4x^{3}-5x&#92;Big]_{2}^{3}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(4&#92;times 3^{3}-5&#92;times 3&#92;big)-&#92;big(4&#92;times 2^{3}-5&#92;times 2&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(4&#92;times 27-15&#92;big)-&#92;big(4&#92;times 8-10&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;(108-15)-(32-10)&#92;&#92;&#92;&#92;&amp;=&amp;93-22&#92;&#92;&#92;&#92;&amp;=&amp;71&#92;end{array} ' title='&#92;begin{array}{rcl}&#92;int_{2}^{3}(12x^{2}-5)&#92; dx&amp;=&amp;&#92;Big[12&#92;times &#92;frac{x^{3}}{3}-5x&#92;Big]_{2}^{3}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;Big[4x^{3}-5x&#92;Big]_{2}^{3}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(4&#92;times 3^{3}-5&#92;times 3&#92;big)-&#92;big(4&#92;times 2^{3}-5&#92;times 2&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(4&#92;times 27-15&#92;big)-&#92;big(4&#92;times 8-10&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;(108-15)-(32-10)&#92;&#92;&#92;&#92;&amp;=&amp;93-22&#92;&#92;&#92;&#92;&amp;=&amp;71&#92;end{array} ' class='latex' /></p>
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			<media:title type="html">Kalakay</media:title>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (37)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-37/</link>
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		<pubDate>Tue, 03 May 2011 03:49:04 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5135</guid>
		<description><![CDATA[Jawaban: C Grafiknya: Perhatikan bahwa batas daerah bagian atas berupa garis lurus dan batas daerah bagian bawah berupa parabola, sehingga: Menentukan batas pengintegralan: Luas daerah antara kedua kurva tersebut adalah: Trik Jitu: Luas daerah antara kedua kurva tersebut adalah:<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5135&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=Luas%5C+daerah%5C+antara%5C+kurva%5C+y%3Dx%5E2%2B2%5C+dan%5C+y%3Dx%2B4%5C+adalah%5C+....%5C%5C%5C%5CA.%5C+%5C+%5Cfrac%7B1%7D%7B2%7D%5C+satuan%5C+luas%5C%5C%5C%5C+B.%5C+%5C+2%5Cfrac%7B5%7D%7B6%7D%5C+satuan%5C+luas%5C%5C%5C%5CC.%5C+%5C+4%5Cfrac%7B1%7D%7B2%7D%5C+satuan%5C+luas%5C%5C%5C%5CD.%5C+%5C+5%5Cfrac%7B1%7D%7B2%7D%5C+satuan%5C+luas%5C%5C%5C%5CE.%5C+%5C+7%5Cfrac%7B1%7D%7B2%7D%5C+satuan%5C+luas+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Luas&#92; daerah&#92; antara&#92; kurva&#92; y=x^2+2&#92; dan&#92; y=x+4&#92; adalah&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; &#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92; B.&#92; &#92; 2&#92;frac{5}{6}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;C.&#92; &#92; 4&#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;D.&#92; &#92; 5&#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;E.&#92; &#92; 7&#92;frac{1}{2}&#92; satuan&#92; luas ' title='Luas&#92; daerah&#92; antara&#92; kurva&#92; y=x^2+2&#92; dan&#92; y=x+4&#92; adalah&#92; ....&#92;&#92;&#92;&#92;A.&#92; &#92; &#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92; B.&#92; &#92; 2&#92;frac{5}{6}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;C.&#92; &#92; 4&#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;D.&#92; &#92; 5&#92;frac{1}{2}&#92; satuan&#92; luas&#92;&#92;&#92;&#92;E.&#92; &#92; 7&#92;frac{1}{2}&#92; satuan&#92; luas ' class='latex' /><br />
Jawaban: C<br />
<img src='http://s0.wp.com/latex.php?latex=y%3Dx%5E2%2B2%5C%5CPersamaan%5C+fungsi%5C+kuadrat%2C%5C+grafiknya%5C+berupa%5C+parabola%5C+terbuka%5C+ke%5C+atas%5C%5C%28karena%5C+koefisien%5C+x%5E%7B2%7D%5C+bertanda%5C+positif%29%5C%5Cy%3Dx%2B4%5C%5CPersamaan%5C+fungsi%5C+linear%2C%5C+grafiknya%5C+berupa%5C+garis%5C+lurus%5C+miring%5C+ke%5C+kanan%5C%5C%28karena%5C+koefisien%5C+x%5C+bertanda%5C+positif%29+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y=x^2+2&#92;&#92;Persamaan&#92; fungsi&#92; kuadrat,&#92; grafiknya&#92; berupa&#92; parabola&#92; terbuka&#92; ke&#92; atas&#92;&#92;(karena&#92; koefisien&#92; x^{2}&#92; bertanda&#92; positif)&#92;&#92;y=x+4&#92;&#92;Persamaan&#92; fungsi&#92; linear,&#92; grafiknya&#92; berupa&#92; garis&#92; lurus&#92; miring&#92; ke&#92; kanan&#92;&#92;(karena&#92; koefisien&#92; x&#92; bertanda&#92; positif) ' title='y=x^2+2&#92;&#92;Persamaan&#92; fungsi&#92; kuadrat,&#92; grafiknya&#92; berupa&#92; parabola&#92; terbuka&#92; ke&#92; atas&#92;&#92;(karena&#92; koefisien&#92; x^{2}&#92; bertanda&#92; positif)&#92;&#92;y=x+4&#92;&#92;Persamaan&#92; fungsi&#92; linear,&#92; grafiknya&#92; berupa&#92; garis&#92; lurus&#92; miring&#92; ke&#92; kanan&#92;&#92;(karena&#92; koefisien&#92; x&#92; bertanda&#92; positif) ' class='latex' /><br />
Grafiknya:<br />
<a href="http://qedems.files.wordpress.com/2011/05/luas-2-kurva.png"><img class="alignnone size-full wp-image-5141" title="Luas 2 kurva" src="http://qedems.files.wordpress.com/2011/05/luas-2-kurva.png?w=750" alt=""   /></a><br />
Perhatikan bahwa batas daerah bagian atas berupa garis lurus dan batas daerah bagian bawah berupa parabola, sehingga:<br />
<img src='http://s0.wp.com/latex.php?latex=y_%7B1%7D%3Dx%2B4%5C+%5C+dan%5C+%5C+y_%7B2%7D%3Dx%5E2%2B2+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y_{1}=x+4&#92; &#92; dan&#92; &#92; y_{2}=x^2+2 ' title='y_{1}=x+4&#92; &#92; dan&#92; &#92; y_{2}=x^2+2 ' class='latex' /><br />
<strong>Menentukan batas pengintegralan</strong>:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7Dy_%7B1%7D%26%3D%26y_%7B2%7D%5C%5Cx%2B4%26%3D%26x%5E2%2B2%5C%5Cx%2B4-x%5E2-2%26%3D%260%5C%5C-x%5E2%2Bx%2B2%26%3D%260%5C%5C-x%5E2%2Bx%2B2%26%3D%260%5C%5Cx%5E2-x-2%26%3D%260%5C%5C%28x-2%29%28x%2B1%29%26%3D%260%5C%5Cx-2%3D0%26atau%26x%2B1%3D0%5C%5Cx%3D2%26atau%26x%3D-1%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}y_{1}&amp;=&amp;y_{2}&#92;&#92;x+4&amp;=&amp;x^2+2&#92;&#92;x+4-x^2-2&amp;=&amp;0&#92;&#92;-x^2+x+2&amp;=&amp;0&#92;&#92;-x^2+x+2&amp;=&amp;0&#92;&#92;x^2-x-2&amp;=&amp;0&#92;&#92;(x-2)(x+1)&amp;=&amp;0&#92;&#92;x-2=0&amp;atau&amp;x+1=0&#92;&#92;x=2&amp;atau&amp;x=-1&#92;end{array} ' title='&#92;begin{array}{rcl}y_{1}&amp;=&amp;y_{2}&#92;&#92;x+4&amp;=&amp;x^2+2&#92;&#92;x+4-x^2-2&amp;=&amp;0&#92;&#92;-x^2+x+2&amp;=&amp;0&#92;&#92;-x^2+x+2&amp;=&amp;0&#92;&#92;x^2-x-2&amp;=&amp;0&#92;&#92;(x-2)(x+1)&amp;=&amp;0&#92;&#92;x-2=0&amp;atau&amp;x+1=0&#92;&#92;x=2&amp;atau&amp;x=-1&#92;end{array} ' class='latex' /><br />
Luas daerah antara kedua kurva tersebut adalah:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DL%26%3D%26%5Cint_%7B-1%7D%5E%7B2%7D%28y_%7B1%7D-y_%7B2%7D%29%5C+dx%5C%5C%5C%5C%26%3D%26%5Cint_%7B-1%7D%5E%7B2%7D%5Cbig%28x%2B4-%28x%5E2%2B2%29%5Cbig%29%5C+dx%5C%5C%5C%5C%26%3D%26%5Cint_%7B-1%7D%5E%7B2%7D%28x%2B4-x%5E%7B2%7D-2%29%5C+dx%5C%5C%5C%5C%26%3D%26%5Cint_%7B-1%7D%5E%7B2%7D%28-x%5E%7B2%7D%2Bx%2B2%29%5C+dx%5C%5C%5C%5C%26%3D%26%5CBig%5B-%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D%2B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%2B2x%5CBig%5D_%7B-1%7D%5E%7B2%7D%5C%5C%5C%5C%26%3D%26%5Cbig%28-%5Cfrac%7B2%5E%7B3%7D%7D%7B3%7D%2B%5Cfrac%7B2%5E%7B2%7D%7D%7B2%7D%2B2.2%5Cbig%29-%5Cbig%28-%5Cfrac%7B%28-1%29%5E%7B3%7D%7D%7B3%7D%2B%5Cfrac%7B%28-1%29%5E%7B2%7D%7D%7B2%7D%2B2.%28-1%29%5Cbig%29%5C%5C%5C%5C%26%3D%26%5Cbig%28-%5Cfrac%7B8%7D%7B3%7D%2B2%2B4%5Cbig%29-%5Cbig%28%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B2%7D-2%5Cbig%29%5C%5C%5C%5C%26%3D%26-%5Cfrac%7B8%7D%7B3%7D%2B6-%5Cfrac%7B1%7D%7B3%7D-%5Cfrac%7B1%7D%7B2%7D%2B2%5C%5C%5C%5C%26%3D%268-%5Cfrac%7B9%7D%7B3%7D-%5Cfrac%7B1%7D%7B2%7D%5C%5C%5C%5C%26%3D%264%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=1' alt='&#92;begin{array}{rcl}L&amp;=&amp;&#92;int_{-1}^{2}(y_{1}-y_{2})&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}&#92;big(x+4-(x^2+2)&#92;big)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}(x+4-x^{2}-2)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}(-x^{2}+x+2)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;Big[-&#92;frac{x^{3}}{3}+&#92;frac{x^{2}}{2}+2x&#92;Big]_{-1}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(-&#92;frac{2^{3}}{3}+&#92;frac{2^{2}}{2}+2.2&#92;big)-&#92;big(-&#92;frac{(-1)^{3}}{3}+&#92;frac{(-1)^{2}}{2}+2.(-1)&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(-&#92;frac{8}{3}+2+4&#92;big)-&#92;big(&#92;frac{1}{3}+&#92;frac{1}{2}-2&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;-&#92;frac{8}{3}+6-&#92;frac{1}{3}-&#92;frac{1}{2}+2&#92;&#92;&#92;&#92;&amp;=&amp;8-&#92;frac{9}{3}-&#92;frac{1}{2}&#92;&#92;&#92;&#92;&amp;=&amp;4&#92;frac{1}{2}&#92;end{array} ' title='&#92;begin{array}{rcl}L&amp;=&amp;&#92;int_{-1}^{2}(y_{1}-y_{2})&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}&#92;big(x+4-(x^2+2)&#92;big)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}(x+4-x^{2}-2)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;int_{-1}^{2}(-x^{2}+x+2)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;Big[-&#92;frac{x^{3}}{3}+&#92;frac{x^{2}}{2}+2x&#92;Big]_{-1}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(-&#92;frac{2^{3}}{3}+&#92;frac{2^{2}}{2}+2.2&#92;big)-&#92;big(-&#92;frac{(-1)^{3}}{3}+&#92;frac{(-1)^{2}}{2}+2.(-1)&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;&#92;big(-&#92;frac{8}{3}+2+4&#92;big)-&#92;big(&#92;frac{1}{3}+&#92;frac{1}{2}-2&#92;big)&#92;&#92;&#92;&#92;&amp;=&amp;-&#92;frac{8}{3}+6-&#92;frac{1}{3}-&#92;frac{1}{2}+2&#92;&#92;&#92;&#92;&amp;=&amp;8-&#92;frac{9}{3}-&#92;frac{1}{2}&#92;&#92;&#92;&#92;&amp;=&amp;4&#92;frac{1}{2}&#92;end{array} ' class='latex' /></p>
<p><strong><span style="color:#000080;">Trik Jitu</span></strong>:<br />
<img src='http://s0.wp.com/latex.php?latex=Luas%5C+daerah%3D%5Cfrac%7BD%5Csqrt%7BD%7D%7D%7B6a%5E%7B2%7D%7D+&amp;bg=ffffff&amp;fg=aa0000&amp;s=1' alt='Luas&#92; daerah=&#92;frac{D&#92;sqrt{D}}{6a^{2}} ' title='Luas&#92; daerah=&#92;frac{D&#92;sqrt{D}}{6a^{2}} ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7Dy_%7B1%7D-y_%7B2%7D%26%3D%26x%2B4-%28x%5E2%2B2%29%5C%5C%26%3D%26x%2B4-x%5E%7B2%7D-2%5C%5C%26%3D%26-x%5E%7B2%7D%2Bx%2B2%5Cend%7Barray%7D%5C%5Csehingga%5C+diperoleh%3A%5C%5Ca%3D-1%2C%5C+b%3D1%2C%5C+c%3D2%5C%5Cdiskriminan%3A%5C%5C%5Cbegin%7Barray%7D%7Brcl%7DD%26%3D%26b%5E%7B2%7D-4ac%5C%5C%26%3D%261%5E%7B2%7D-4%28-1%29.2%5C%5C%26%3D%261%2B9%5C%5C%26%3D%269%5C%5C%5Csqrt%7BD%7D%26%3D%263%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}y_{1}-y_{2}&amp;=&amp;x+4-(x^2+2)&#92;&#92;&amp;=&amp;x+4-x^{2}-2&#92;&#92;&amp;=&amp;-x^{2}+x+2&#92;end{array}&#92;&#92;sehingga&#92; diperoleh:&#92;&#92;a=-1,&#92; b=1,&#92; c=2&#92;&#92;diskriminan:&#92;&#92;&#92;begin{array}{rcl}D&amp;=&amp;b^{2}-4ac&#92;&#92;&amp;=&amp;1^{2}-4(-1).2&#92;&#92;&amp;=&amp;1+9&#92;&#92;&amp;=&amp;9&#92;&#92;&#92;sqrt{D}&amp;=&amp;3&#92;end{array} ' title='&#92;begin{array}{rcl}y_{1}-y_{2}&amp;=&amp;x+4-(x^2+2)&#92;&#92;&amp;=&amp;x+4-x^{2}-2&#92;&#92;&amp;=&amp;-x^{2}+x+2&#92;end{array}&#92;&#92;sehingga&#92; diperoleh:&#92;&#92;a=-1,&#92; b=1,&#92; c=2&#92;&#92;diskriminan:&#92;&#92;&#92;begin{array}{rcl}D&amp;=&amp;b^{2}-4ac&#92;&#92;&amp;=&amp;1^{2}-4(-1).2&#92;&#92;&amp;=&amp;1+9&#92;&#92;&amp;=&amp;9&#92;&#92;&#92;sqrt{D}&amp;=&amp;3&#92;end{array} ' class='latex' /><br />
Luas daerah antara kedua kurva tersebut adalah:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DL%26%3D%26%5Cfrac%7BD%5Csqrt%7BD%7D%7D%7B6a%5E%7B2%7D%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B9%5Ctimes+3%7D%7B6.%28-1%29%5E%7B2%7D%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B9%5Ctimes+3%7D%7B6.1%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B9%5Ctimes+3%7D%7B6%7D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B9%7D%7B2%7D%5C%5C%5C%5C%26%3D%264%5Cfrac%7B1%7D%7B2%7D%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=aa0000&amp;s=1' alt='&#92;begin{array}{rcl}L&amp;=&amp;&#92;frac{D&#92;sqrt{D}}{6a^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6.(-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6.1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9}{2}&#92;&#92;&#92;&#92;&amp;=&amp;4&#92;frac{1}{2}&#92;end{array} ' title='&#92;begin{array}{rcl}L&amp;=&amp;&#92;frac{D&#92;sqrt{D}}{6a^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6.(-1)^{2}}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6.1}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9&#92;times 3}{6}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{9}{2}&#92;&#92;&#92;&#92;&amp;=&amp;4&#92;frac{1}{2}&#92;end{array} ' class='latex' /></p>
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			<media:title type="html">Kalakay</media:title>
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		<media:content url="http://qedems.files.wordpress.com/2011/05/luas-2-kurva.png" medium="image">
			<media:title type="html">Luas 2 kurva</media:title>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (36)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-36/</link>
		<comments>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-36/#comments</comments>
		<pubDate>Tue, 03 May 2011 00:03:39 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5108</guid>
		<description><![CDATA[Jawaban: Grafiknya: C (Bila Anda kesulitan dalam menggambarkan grafiknya, langsung saja ke perhitungan volumenya) Karena pemutaran mengelilingi sumbu X, maka volumenya adalah:<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5108&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><img src='http://s0.wp.com/latex.php?latex=Volume%5C+benda%5C+putar%5C+yang%5C+terjadi%5C+jika%5C+daerah%5C+yang%5C+dibatasi%5C+garis%5C+y%3Dx-2%2C%5C%5Csumbu%5C+x%2C%5C+garis%5C+x%3D0%5C+dan%5C+x%3D2%5C+diputar%5C+mengelilingi%5C+sumbu%5C+x%5C+sejauh%5C+360%5E%7B%5Ccirc%7D%5C%5Cadalah%5C+....%5C%5C%5C%5CA.+%5C+%5C+%5Cfrac%7B4%7D%7B3%7D%5Cpi+%5C+satuan%5C+volume%5C%5C%5C%5CB.%5C+%5C+2%5Cpi+%5C+satuan%5C+volume%5C%5C%5C%5CC.%5C+%5C+%5Cfrac%7B8%7D%7B3%7D%5Cpi+%5C+satuan%5C+volume%5C%5C%5C%5CD.%5C+%5C+5%5Cpi+%5C+satuan%5C+volume%5C%5C%5C%5CE.%5C+%5C+7%5Cpi+%5C+satuan%5C+volume+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Volume&#92; benda&#92; putar&#92; yang&#92; terjadi&#92; jika&#92; daerah&#92; yang&#92; dibatasi&#92; garis&#92; y=x-2,&#92;&#92;sumbu&#92; x,&#92; garis&#92; x=0&#92; dan&#92; x=2&#92; diputar&#92; mengelilingi&#92; sumbu&#92; x&#92; sejauh&#92; 360^{&#92;circ}&#92;&#92;adalah&#92; ....&#92;&#92;&#92;&#92;A. &#92; &#92; &#92;frac{4}{3}&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;B.&#92; &#92; 2&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;C.&#92; &#92; &#92;frac{8}{3}&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;D.&#92; &#92; 5&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;E.&#92; &#92; 7&#92;pi &#92; satuan&#92; volume ' title='Volume&#92; benda&#92; putar&#92; yang&#92; terjadi&#92; jika&#92; daerah&#92; yang&#92; dibatasi&#92; garis&#92; y=x-2,&#92;&#92;sumbu&#92; x,&#92; garis&#92; x=0&#92; dan&#92; x=2&#92; diputar&#92; mengelilingi&#92; sumbu&#92; x&#92; sejauh&#92; 360^{&#92;circ}&#92;&#92;adalah&#92; ....&#92;&#92;&#92;&#92;A. &#92; &#92; &#92;frac{4}{3}&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;B.&#92; &#92; 2&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;C.&#92; &#92; &#92;frac{8}{3}&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;D.&#92; &#92; 5&#92;pi &#92; satuan&#92; volume&#92;&#92;&#92;&#92;E.&#92; &#92; 7&#92;pi &#92; satuan&#92; volume ' class='latex' /><br />
Jawaban:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DGaris%5C+y%3Dx-2%26%5Crightarrow+%26miring%5C+ke%5C+kanan%5C+karena%5C+koefisien%5C+x%5C+positif%5C%5C%26%5Crightarrow+%26menggeser%5C+garis%5C+y%3Dx%5C+sejauh%5C+2%5C+satuan%5C+ke%5C+arah%5C+bawah%5C+dari%5C+titik%5C+O%5Cend%7Barray%7D%5C%5CGaris%5C+x%3D0%5C+adalah%5C+sumbu%5C+y%5C%5CGaris%5C+x%3D2%5C+adalah%5C+garis%5C+yang%5C+tegak%5C+lurus%5C+sumbu%5C+x%5C+dan%5C+melalui%5C+titik%5C+%282%2C%5C+0%29+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}Garis&#92; y=x-2&amp;&#92;rightarrow &amp;miring&#92; ke&#92; kanan&#92; karena&#92; koefisien&#92; x&#92; positif&#92;&#92;&amp;&#92;rightarrow &amp;menggeser&#92; garis&#92; y=x&#92; sejauh&#92; 2&#92; satuan&#92; ke&#92; arah&#92; bawah&#92; dari&#92; titik&#92; O&#92;end{array}&#92;&#92;Garis&#92; x=0&#92; adalah&#92; sumbu&#92; y&#92;&#92;Garis&#92; x=2&#92; adalah&#92; garis&#92; yang&#92; tegak&#92; lurus&#92; sumbu&#92; x&#92; dan&#92; melalui&#92; titik&#92; (2,&#92; 0) ' title='&#92;begin{array}{rcl}Garis&#92; y=x-2&amp;&#92;rightarrow &amp;miring&#92; ke&#92; kanan&#92; karena&#92; koefisien&#92; x&#92; positif&#92;&#92;&amp;&#92;rightarrow &amp;menggeser&#92; garis&#92; y=x&#92; sejauh&#92; 2&#92; satuan&#92; ke&#92; arah&#92; bawah&#92; dari&#92; titik&#92; O&#92;end{array}&#92;&#92;Garis&#92; x=0&#92; adalah&#92; sumbu&#92; y&#92;&#92;Garis&#92; x=2&#92; adalah&#92; garis&#92; yang&#92; tegak&#92; lurus&#92; sumbu&#92; x&#92; dan&#92; melalui&#92; titik&#92; (2,&#92; 0) ' class='latex' /><br />
Grafiknya: C<br />
<a href="http://qedems.files.wordpress.com/2011/05/integral.png"><img class="alignnone size-full wp-image-5122" title="integral" src="http://qedems.files.wordpress.com/2011/05/integral.png?w=750" alt=""   /></a><br />
(Bila Anda kesulitan dalam menggambarkan grafiknya, langsung saja ke perhitungan volumenya)<br />
Karena pemutaran mengelilingi sumbu X, maka volumenya adalah:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DV%26%3D%26%5Cpi+%5Cint_%7Ba%7D%5E%7Bb%7Dy%5E%7B2%7D%5C+dx%5C%5C%5C%5C%26%3D%26%5Cpi+%5Cint_%7B0%7D%5E%7B2%7D%28x-2%29%5E%7B2%7D%5C+dx%5C%5C%5C%5C%26%3D%26%5Cpi+%5Cint_%7B0%7D%5E%7B2%7D%28x%5E2-4x%2B4%29%5C+dx%5C%5C%5C%5C%26%3D%26%5Cpi+%5Cbig%5B%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D-4%5Ctimes+%5Cfrac%7Bx%5E2%7D%7B2%7D%2B4x%5Cbig%5D_%7B0%7D%5E%7B2%7D%5C%5C%5C%5C%26%3D%26%5Cpi+%5Cbig%5B%5Cfrac%7Bx%5E%7B3%7D%7D%7B3%7D-2x%5E2%2B4x%5Cbig%5D_%7B0%7D%5E%7B2%7D%5C%5C%5C%5C%26%3D%26%5Cpi+%5CBig%5B%5Cbig%28%5Cfrac%7B2%5E%7B3%7D%7D%7B3%7D-2%5Ctimes+2%5E2%2B4.2%5Cbig%29-%5Cbig%28%5Cfrac%7B0%5E%7B3%7D%7D%7B3%7D-2%5Ctimes+0%5E2%2B4.0%5Cbig%29%5CBig%5D%5C%5C%5C%5C%26%3D%26%5Cpi+%5CBig%5B%5Cbig%28%5Cfrac%7B8%7D%7B3%7D-8%2B8%5Cbig%29-%5Cbig%280%5Cbig%29%5CBig%5D%5C%5C%5C%5C%26%3D%26%5Cfrac%7B8%7D%7B3%7D%5Cpi+%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}V&amp;=&amp;&#92;pi &#92;int_{a}^{b}y^{2}&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;int_{0}^{2}(x-2)^{2}&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;int_{0}^{2}(x^2-4x+4)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;big[&#92;frac{x^{3}}{3}-4&#92;times &#92;frac{x^2}{2}+4x&#92;big]_{0}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;big[&#92;frac{x^{3}}{3}-2x^2+4x&#92;big]_{0}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;Big[&#92;big(&#92;frac{2^{3}}{3}-2&#92;times 2^2+4.2&#92;big)-&#92;big(&#92;frac{0^{3}}{3}-2&#92;times 0^2+4.0&#92;big)&#92;Big]&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;Big[&#92;big(&#92;frac{8}{3}-8+8&#92;big)-&#92;big(0&#92;big)&#92;Big]&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{8}{3}&#92;pi &#92;end{array} ' title='&#92;begin{array}{rcl}V&amp;=&amp;&#92;pi &#92;int_{a}^{b}y^{2}&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;int_{0}^{2}(x-2)^{2}&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;int_{0}^{2}(x^2-4x+4)&#92; dx&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;big[&#92;frac{x^{3}}{3}-4&#92;times &#92;frac{x^2}{2}+4x&#92;big]_{0}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;big[&#92;frac{x^{3}}{3}-2x^2+4x&#92;big]_{0}^{2}&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;Big[&#92;big(&#92;frac{2^{3}}{3}-2&#92;times 2^2+4.2&#92;big)-&#92;big(&#92;frac{0^{3}}{3}-2&#92;times 0^2+4.0&#92;big)&#92;Big]&#92;&#92;&#92;&#92;&amp;=&amp;&#92;pi &#92;Big[&#92;big(&#92;frac{8}{3}-8+8&#92;big)-&#92;big(0&#92;big)&#92;Big]&#92;&#92;&#92;&#92;&amp;=&amp;&#92;frac{8}{3}&#92;pi &#92;end{array} ' class='latex' /></p>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (35)</title>
		<link>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-35/</link>
		<comments>http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-35/#comments</comments>
		<pubDate>Mon, 02 May 2011 21:10:30 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5095</guid>
		<description><![CDATA[Suatu pabrik pada bulan pertama memproduksi 120 tas. Setiap bulan produksi mengalami pertambahan tetap sebanyak 15 tas. Banyak tas yang diproduksi pada tahun pertama adalah &#8230;. A. 1.215 tas                     B. 1.710 tas                     C. 2.430 tas                     D. 2.520 tas                     E. 4.860 tas Jawaban: C Karena produksi mengalami pertambahan tetap maka ini adalah masalah deret aritmetika. &#8230; <a href="http://qedems.wordpress.com/2011/05/03/solusi-paket-59-un-2011-matematika-smk-teknologi-35/">Continue reading <span class="meta-nav">&#187;</span></a><img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5095&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Suatu pabrik pada bulan pertama memproduksi 120 tas. Setiap bulan produksi mengalami pertambahan tetap sebanyak 15 tas. Banyak tas yang diproduksi pada tahun pertama adalah &#8230;.<br />
A. 1.215 tas                     B. 1.710 tas                     C. 2.430 tas                     D. 2.520 tas                     E. 4.860 tas<br />
Jawaban: C<br />
Karena produksi mengalami pertambahan tetap maka ini adalah masalah deret aritmetika.<br />
Diketahui:<br />
<img src='http://s0.wp.com/latex.php?latex=suku%5C+pertama%5Cqquad+%5Crightarrow+%5Cqquad+a%3D120%5C%5Cbeda%5Cqquad+%5Cqquad+%5Cqquad+%5C+%5Crightarrow+%5Cqquad+b%3D15+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='suku&#92; pertama&#92;qquad &#92;rightarrow &#92;qquad a=120&#92;&#92;beda&#92;qquad &#92;qquad &#92;qquad &#92; &#92;rightarrow &#92;qquad b=15 ' title='suku&#92; pertama&#92;qquad &#92;rightarrow &#92;qquad a=120&#92;&#92;beda&#92;qquad &#92;qquad &#92;qquad &#92; &#92;rightarrow &#92;qquad b=15 ' class='latex' /><br />
Karena 1 tahun = 12 bulan, maka banyak tas yang diproduksi pada tahun pertama adalah jumlah 12 suku pertama dari deret tersebut, yaitu:<br />
<img src='http://s0.wp.com/latex.php?latex=S_%7Bn%7D%3D%5Cfrac%7Bn%7D%7B2%7D%5Cbig%282a%2B%28n-1%29b%5Cbig%29+&amp;bg=ffffff&amp;fg=aa0000&amp;s=0' alt='S_{n}=&#92;frac{n}{2}&#92;big(2a+(n-1)b&#92;big) ' title='S_{n}=&#92;frac{n}{2}&#92;big(2a+(n-1)b&#92;big) ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DS_%7B12%7D%26%3D%26%5Cfrac%7B12%7D%7B2%7D%5Cbig%282%5Ctimes+120%2B%2812-1%2915%5Cbig%29%5C%5C%26%3D%266%28240%2B11%5Ctimes+15%29%5C%5C%26%3D%266%28240%2B165%29%5C%5C%26%3D%266%28405%29%5C%5C%26%3D%262.430%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}S_{12}&amp;=&amp;&#92;frac{12}{2}&#92;big(2&#92;times 120+(12-1)15&#92;big)&#92;&#92;&amp;=&amp;6(240+11&#92;times 15)&#92;&#92;&amp;=&amp;6(240+165)&#92;&#92;&amp;=&amp;6(405)&#92;&#92;&amp;=&amp;2.430&#92;end{array} ' title='&#92;begin{array}{rcl}S_{12}&amp;=&amp;&#92;frac{12}{2}&#92;big(2&#92;times 120+(12-1)15&#92;big)&#92;&#92;&amp;=&amp;6(240+11&#92;times 15)&#92;&#92;&amp;=&amp;6(240+165)&#92;&#92;&amp;=&amp;6(405)&#92;&#92;&amp;=&amp;2.430&#92;end{array} ' class='latex' /></p>
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			<media:title type="html">Kalakay</media:title>
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		<title>Solusi Paket 59 UN 2011 Matematika SMK Teknologi (34)</title>
		<link>http://qedems.wordpress.com/2011/05/02/solusi-paket-59-un-2011-matematika-smk-teknologi-34/</link>
		<comments>http://qedems.wordpress.com/2011/05/02/solusi-paket-59-un-2011-matematika-smk-teknologi-34/#comments</comments>
		<pubDate>Mon, 02 May 2011 12:17:23 +0000</pubDate>
		<dc:creator>Kalakay</dc:creator>
				<category><![CDATA[SMK Teknologi dan Rekayasa]]></category>
		<category><![CDATA[Solusi UN 2011 SMK Teknologi]]></category>

		<guid isPermaLink="false">http://qedems.wordpress.com/?p=5084</guid>
		<description><![CDATA[Proses menghitung modus dari data di samping adalah &#8230;. Jawaban: C Rumus Modus data berkelompok:<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=qedems.wordpress.com&amp;blog=6208195&amp;post=5084&amp;subd=qedems&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Proses menghitung modus dari data di samping adalah &#8230;.<a href="http://qedems.files.wordpress.com/2011/05/modus.png"><img class="alignright size-full wp-image-5088" title="Modus" src="http://qedems.files.wordpress.com/2011/05/modus.png?w=750" alt=""   /></a><br />
<img src='http://s0.wp.com/latex.php?latex=A.%5C+%5C+Mo%3D18%2C5%2B%5CBig%28%5Cfrac%7B4%7D%7B2%2B4%7D%5CBig%293%5C%5C%5C%5CB.%5C+%5C+Mo%3D18%2C5%2B%5CBig%28%5Cfrac%7B4%7D%7B4%2B4%7D%5CBig%293%5C%5C%5C%5CC.%5C+%5C+Mo%3D18%2C5%2B%5CBig%28%5Cfrac%7B2%7D%7B2%2B4%7D%5CBig%293%5C%5C%5C%5CD.%5C+%5C+Mo%3D20%2C5%2B%5CBig%28%5Cfrac%7B2%7D%7B2%2B4%7D%5CBig%293%5C%5C%5C%5CE.%5C+%5C+Mo%3D20%2C5%2B%5CBig%28%5Cfrac%7B2%7D%7B2%2B2%7D%5CBig%293+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='A.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{4}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;B.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{4}{4+4}&#92;Big)3&#92;&#92;&#92;&#92;C.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;D.&#92; &#92; Mo=20,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;E.&#92; &#92; Mo=20,5+&#92;Big(&#92;frac{2}{2+2}&#92;Big)3 ' title='A.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{4}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;B.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{4}{4+4}&#92;Big)3&#92;&#92;&#92;&#92;C.&#92; &#92; Mo=18,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;D.&#92; &#92; Mo=20,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3&#92;&#92;&#92;&#92;E.&#92; &#92; Mo=20,5+&#92;Big(&#92;frac{2}{2+2}&#92;Big)3 ' class='latex' /><br />
Jawaban: C<br />
<span style="color:#0000ff;">Rumus Modus data berkelompok</span>:<br />
<img src='http://s0.wp.com/latex.php?latex=%5Cmathbf%7BModus%3DTb%2B%5Cleft+%28%5Cfrac%7Bd_%7B1%7D%7D%7Bd_%7B1%7D%2Bd_%7B2%7D%7D+%5Cright+%29i%7D+&amp;bg=ffffff&amp;fg=aa0000&amp;s=0' alt='&#92;mathbf{Modus=Tb+&#92;left (&#92;frac{d_{1}}{d_{1}+d_{2}} &#92;right )i} ' title='&#92;mathbf{Modus=Tb+&#92;left (&#92;frac{d_{1}}{d_{1}+d_{2}} &#92;right )i} ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=%5Cbegin%7Barray%7D%7Brcl%7DKelas%5C+modus%26%3D%2619%5C+-%5C+21%5C%5CTb%26%3D%2619-0%2C5%3D18%2C5%5C%5Cd_%7B1%7D%26%3D%2610-8%3D2%5C%5Cd_%7B2%7D%26%3D%2610-6%3D4%5C%5Ci%26%3D%2616-13%3D3%5Cend%7Barray%7D+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;begin{array}{rcl}Kelas&#92; modus&amp;=&amp;19&#92; -&#92; 21&#92;&#92;Tb&amp;=&amp;19-0,5=18,5&#92;&#92;d_{1}&amp;=&amp;10-8=2&#92;&#92;d_{2}&amp;=&amp;10-6=4&#92;&#92;i&amp;=&amp;16-13=3&#92;end{array} ' title='&#92;begin{array}{rcl}Kelas&#92; modus&amp;=&amp;19&#92; -&#92; 21&#92;&#92;Tb&amp;=&amp;19-0,5=18,5&#92;&#92;d_{1}&amp;=&amp;10-8=2&#92;&#92;d_{2}&amp;=&amp;10-6=4&#92;&#92;i&amp;=&amp;16-13=3&#92;end{array} ' class='latex' /><br />
<img src='http://s0.wp.com/latex.php?latex=Modus%3D18%2C5%2B%5CBig%28%5Cfrac%7B2%7D%7B2%2B4%7D%5CBig%293+&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='Modus=18,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3 ' title='Modus=18,5+&#92;Big(&#92;frac{2}{2+4}&#92;Big)3 ' class='latex' /></p>
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			<media:title type="html">Kalakay</media:title>
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